|  You must congratulate me, for this is my most outrageous title 
                    yet. In fact, is has little to do with transonic flow at all. 
                    This time we are going to look at the pure subsonic flow problem, 
                    below M = 0.7 . Well, why bother?
  At the heart of propeller design is the question of how 
                    much lift we can generate efficiently for each radial station 
                    along the blade. As we have seen, the flow problem in the 
                    transonic region is little short of catastrophic. Even if 
                    the tips aren’t blowing air backwards, they can sure 
                    be soaking up engine power without giving much in return. 
                    Hence the need for special airfoil sections, which are little 
                    documented in the lay aerodynamics press.   But even for subsonic flow, there are still problems. For 
                    a start, try finding data for airfoils with low Reynolds number 
                    and Mach numbers around 0.5. We can always assign a value 
                    for the lift coefficient, but what about the zero-lift angle 
                    of these airfoils? What we need are some rules for handling 
                    the aerodynamics from M = 0 to M = .7. Luckily they exist 
                    and are quite good enough, but first let’s have some 
                    fun.   Here is a very fundamental formula for lift force, L:   
                    
  First note the mixture of Greek symbols with Roman. That 
                    is a good tip-off. If it’s all in Greek characters, 
                    the author is not confused: muddled, even wrong, but not confused. 
                    If it’s all in Roman, he is uncultured. But mixed Greek 
                    and Roman? I am now going to explain this formula to you exactly 
                    as it is written.    is 
                    the air density. 0.5 is 0.5. Cl is a constant of proportionality 
                    called the “lift-coefficient”. Note the violation 
                    of the spelling rule “i before e except after c”. 
                    Also, Cl is not a constant, but is in fact a function of Reynolds 
                    and Mach numbers. What is more, if you look this number up 
                    in tables, you will find that it applies to a wing of infinite 
                    aspect ratio. We can live with that. V is the velocity of 
                    the airplane with the assumption that air is incompressible. 
                    In fact, air is highly compressible, but that is merely an 
                    inconvenient truth. Finally, S is the area of the infinitely 
                    long wing, so its value is the mean chord times infinity.  So we have a nice, simple formula that is about as useful, 
                    in the words of my master Andy Kerr, as tits on a bull. We 
                    shall return to this quantity Cl after a brief word from our 
                    sponsor.  I did mention a problem in finding the zero-lift angle ao 
                    of a fully subsonic airfoil. Well it turns out that there 
                    are some nice solutions to this problem based on thin airfoil 
                    theory. Abbott and Von Doenhoff give methods on page 72 attributed 
                    to Munk and separately to Pankhurst, which are quite adequate. 
                    I don’t use them, because they give the same result 
                    as a much simpler expression given by….I can’t 
                    remember! But here it is anyway   
                      where  
                      = zero lift angle in degrees m = airfoil camber … typical value .0355
 p = camber line high point … typical value .4
 rtd= conversion factor radians to degrees [180/
  } ATN is the trigonometric operation arc tan
 For these typical values, we get
  = -3.38 which is not too different from the value found in Soartech 8 at low Reynolds number for Clark Y.
  We are nearly ready to move on. Just one more thing. There 
                    is a thing called the lift-slope. Bad English, so it must 
                    be American. When you increase the angle of attack of an airfoil, 
                    you get more lift. Surprisingly, for most thin airfoils, the 
                    value of the lift-slope is pretty well constant. That value 
                    is 0.09 degree^(-1). Good god, what? Let’s try an example.   Choose an angle, say 5 degrees. Then the lift coefficient 
                    increases by 5 * .09 = .45 Typically, for most reasonable 
                    airfoils, the lift coefficient varies from -0.2 to 0.85. Above 
                    0.85, the airfoil is getting close to the stall. Below -0.2, 
                    we are looking at a cambered airfoil which is about to do 
                    a negative stall!   So to review. We have a thing called lift-coefficient. Also 
                    a thing called zero-lift angle and yet another thing called 
                    lift-slope. If you have those things figured, we can move 
                    on.   What we are looking for is the behaviour of the lift coefficient 
                    as affected by Mach number. In figure 2 below, look at the 
                    red and yellow curves for Mach number less than 0.7. Mach 
                    numbers below 0.7 are generally “subsonic”. There 
                    is no point on the airfoil where the local flow has exceeded 
                    Mach 1. We are not dealing with the shock-waves which gave 
                    us the horrors in the transonic region. 
 
 Both these airfoils show an increase in the lift coefficient 
                    as the Mach number increases. There is a rather greater increase 
                    for the yellow airfoil than the red, which is confounding. 
                    For this exercise, we will pretend they are the same!
 This increase in lift coefficient with Mach number is a compressibility 
                    effect. There is a very simple formula which allows us to 
                    calculate this increase in lift coefficient. The formula is 
                    called by Milne-Thompson the “Glauert correction”, 
                    and by other authors as the “Glauert-Prandtl rule”. 
                    It is of great value to propeller designers, as virtually 
                    every propeller has a strong radial change in Mach number 
                    from root to tip. In F3D and F2A, this change ranges from 
                    0 out to .95, which is really quite a problem.
 If this rule lets us cover the subsonic region, then at least 
                    we have that covered. But just what is this rule, and how 
                    may it be applied? Well, first let me have a moan. For years 
                    I have been aware of this rule, but being a simple soul I 
                    could not see how to apply it. In my defence, let me quote 
                    from some texts.   First off the rank is Godsey and Young, ”Gas Turbines 
                    for Aircraft”, 1949. Try this for a mouthful.   “Consider a flow with free-stream Mach number Mo over 
                    a thin airfoil of thickness t set at an angle 
					 . 
                    The drag and lift are affected by compressibility as if the 
                    flow were an incompressible one for a similar airfoil having 
                    thickness, not t, but t /  (1-Mo^2): 
                    having angle of attack, not a, but  /  (1-Mo^2): 
                    and having its camber increased in the ratio 1 /
  (1-Mo^2).”  I can still remember the first time I read this. I was on 
                    the bus heading home from the reactor site. If only Nuclear 
                    Physics were as clear as this. All I had to do was find data 
                    for an airfoil stretched in 3 different directions and the 
                    job was done. I don’t think!   Next off the rank is my old mate Milne-Thompson in “Theoretical 
                    Aerodynamics”, who threw in a lot of mathematical chaff 
                    with the oats. Try this:   “Case I.   = 1, 
					v 
                    = 1. Here the chords are equal but the camber and thickness 
                    of A are those of Ai, reduced in the ratio ß:1. The 
                    lift, circulation, and pressure are the same at corresponding 
                    points in both flows. The incidence is reduced in the ratio 
                    ß:1.  Case II.  
					  = 1/ß,
					
					v 
                    = 1. Now c =  
					ßci, so that the chord of A is less than 
                    the chord of Ai in the ratio ß:1 and the camber and 
                    thickness are reduced in the same ratio at corresponding points. 
                    The lift, shape, incidence and circulation are unaltered; 
                    the pressure is increased in the ratio 1:ß.  Case III.   = 1, v 
                    = ß. In this case ß/  
					v 
                    = 1 and the distortions are the same in both flows. Thus A 
                    and Ai are identical profiles at the same incidence. The circulation, 
                    lift and pressure are increased in the ratio 1:ß. Thus 
                    the effect of compressibility on a  
					given 
                    profile is to increase the lift in the ratio 1:ß. 
					“  End quote. That very last line is the clue. No more bending 
                    and twisting the airfoil profile. This is the same airfoil 
                    we started with. Compressibility changes its lift. Good old 
                    Milne-Thommo.   Perhaps I could have saved myself some trouble if I had 
                    understood Abbott and Von Doenhoff’s conttribbution. 
                    “The Glauert-Prandtl rule relates the lift coefficient 
                    or slope of the lift curve of a wing section in compressible 
                    flow with that for incompressible flow”.  
                     
  With c 
                    meaning “compressible” and i 
                    meaning “incompressible”, this works. But I still 
                    can’t see how it works for the lift slope. Guess I’ll 
                    just have to stay thin and ignorant. |